Since we have two dices and we want to know the events where the first one shows an odd number and the second die shows a number larger than 4, we have that the following results are the ones that fit the requirement:
[tex](1,5),(1,6),(3,5),(3,6),(5,5),(5,6)[/tex]Now, we know that the sample space has 6x6=36 possible outcomes, therefore, the desired probability is:
[tex]P(\text{odd,x}>4)=\frac{6}{36}=\frac{1}{6}[/tex]therefore, the probability is 1/6
