The image of the line provided seems to go through the following points:
(0, 4) , (-4, 5), and (4, 3)
Knowing at least two points is essential to calculate the slope via the formula:
[tex]\text{slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]
so, for example if we use the points (0, 4) and (-4, 5) to calculate the slope, we get:
[tex]\text{slope}=\frac{5-4}{-4-0}=-\frac{1}{4}[/tex]
Therefore, the slope is -1/4 (negative one fourth)
Notice as well that one of the points we chose is (0, 4) which in fact is the y-intercept of the line (the point at which the line crosses the y-axis ).
so we have al the elements to built the equation of this line:
slope = -1/4
y intercept = 4 for the (0, 4) on the plane
Then the equation could be built using:
y = (-1/4) x + 4
