Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AC = 15 and DC = 6, what is the length of BC in simplest radical form? (Note: the figure is not drawn to scale.) B х A D 6 C с 15 Submit Answer Answer: I

Respuesta :

Answer

BC = x = 3√10

Explanation

To answer this question, we will use the concept of similar triangles.

We know that the two triangles ABC and BDC are similar because they are right angle triangles with one common non-right angle angle too, Angle C.

Using angle C as a reference point, we can write the corresponding sides.

And we know that corresponding sides for similar triangles have the same ratio.

∆ABC = ∆BDC

AB is corresponding to BD

BC is corresponding to DC

CA is corresponding to CB

So,

(AB/BD) = (BC/DC) = (CA/CB)

The sides that we need include

BC, DC, CA and CB

BC = x

DC = 6

CA = 15

CB = x

(BC/DC) = (CA/CB)

(x/6) = (15/x)

Cross multiply

x² = (6)(15)

x² = 90

Take the square root of both sides

√(x²) = √(90)

x = √90

x = √[(9)(10)]

x = (√9) (√10)

x = 3√10

Hope this Helps!!!