In a game, a spinner with 8 equally sized sections numbered 1 to 8 is spun and a die is tossed. What is the probability of landing on an odd number on the spinner and rolling aneven number on the die?

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ANSWER

1/4

EXPLANATION

The spinner has 8 equally sized sections numbered 1 to 8.

The die has 6 faces.

On the spinner there are 4 sections with odd numbers and 4 sections with even numbers.

On a die, there are 3 faces with even numbers and 3 faces with odd numbers.

To find the probability of both events occuring, we need to find their individual probabilities and then multiply them together.

The probability of landing on an odd number on the spinner is:

4/8 i.e. 1/2

The probability of rolling an even number on the die is:

3/6 i.e. 1/2

Therefore, the probability of landing on an odd number on the spinner and rolling an even number on the die is:

[tex]\begin{gathered} \frac{1}{2}\cdot\text{ }\frac{1}{2} \\ \text{= }\frac{1}{4} \end{gathered}[/tex]