Given the equation:
[tex]\frac{\frac{3}{5}}{\frac{14}{2}}=\frac{\frac{1}{2}}{\frac{35}{6}}[/tex]
Let's determine if the proportion is a true proportion.
If the proportionis true, it means the ratio on both sides if the equality are equal.
Now, let's find the ratios.
For the first ratio:
[tex]\begin{gathered} \frac{\frac{3}{5}}{\frac{14}{2}} \\ \\ =\frac{3}{5}\div\frac{14}{2} \\ \\ \text{ Flip the fraction on the right and change the division symbol to mutilication:} \\ =\frac{3}{5}\times\frac{2}{14} \\ \\ =\frac{3}{5}\times\frac{1}{7} \\ \\ =\frac{3\times1}{5\times7} \\ \\ =\frac{3}{35} \end{gathered}[/tex]
For the second ratio:
[tex]\begin{gathered} \frac{\frac{1}{2}}{\frac{35}{6}} \\ \\ =\frac{1}{2}\div\frac{35}{6} \\ \\ \text{ Flip the fraction on the right and change the division symbol to mutilication:} \\ =\frac{1}{2}\times\frac{6}{35} \\ \\ =\frac{1\times6}{2\times35} \\ \\ =\frac{6}{70} \\ \\ =\frac{3}{35} \end{gathered}[/tex]
After simlifying, we have:
[tex]\frac{3}{35}=\frac{3}{35}[/tex]
Since the equation is true, we can say the proortion is true because it has a constant ratio.
