If PQRS is a parallelogram, we know that:
- PS and QR have the same length.
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Then, we can calculate x as:
[tex]\begin{gathered} PS=QR \\ 13x+15=19x-9 \\ 13x-19x=-9-15 \\ -6x=-24 \\ x=\frac{-24}{-6} \\ x=4 \end{gathered}[/tex]
And we can calculate y as:
[tex]\begin{gathered} m\angle Q+m\angle R=180\degree \\ (4y+7)+(10y-37)=180 \\ 14y-30=180 \\ 14y=180+30 \\ 14y=210 \\ y=\frac{210}{14} \\ y=15 \end{gathered}[/tex]
Answer: x=4 and y=15
