Respuesta :
Answer: There are 0.375 moles of neon gas present in the testing chamber.
Explanation:
The question requires us to calculate the number of moles of neon gas, given that the gas is in a 2.50 L chamber at 325.0 K and the pressure inside the chamber is 4.00 atm.
We can solve this problem using the equation for ideal gases, as shown below:
[tex]PV=nRT[/tex]where P is the pressure of the gas (P = 4.00 atm), V is the volume of the gas (V = 2.50 L), n is the number of moles, that we want to calculate, T is the temperature of the gas (T = 325.0 K) and R is the gas constant.
Note that the values of pressure and volume are given in atm and L, respectively. Therefore, we can apply the gas constant in units of L.atm/mol.K:
R = 0.082057 L.atm/K.mol
First, let's rearrange the equation of ideal gases in order to calculate the number of moles of gas:
[tex]PV=nRT\rightarrow n=\frac{PV}{RT}[/tex]Now, applying the values given by the question and the constant R, we'll have:
[tex]n=\frac{(4.00atm)\times(2.50L)}{(0.082057L.atm/K.mol)\times(325.0K)}=0.375mol[/tex]Therefore, there are 0.375 moles of neon gas in the testing chamber under the conditions given by the question.
