Answer:
• x=3
,• y=-2
Explanation:
Given the linear system of the equations:
[tex]\begin{gathered} 4x+2y=8\cdots\cdots\cdots(1) \\ 2x+2y=2\cdots\cdots\cdots(2) \end{gathered}[/tex]First, subtract equation(2) from equation(1).
[tex]\begin{gathered} (4x-2x)+(2y-2y)=8-2 \\ 2x=6 \\ \text{Divide both sides by 2} \\ \frac{2x}{2}=\frac{6}{2} \\ x=3 \end{gathered}[/tex]Next, substitute x=3 into equation (1) to solve for y.
[tex]\begin{gathered} 4x+2y=8\cdots\cdots\cdots(1) \\ 4(3)+2y=8 \\ 12+2y=8 \\ \text{Subtract 12 from both sides.} \\ 12-12+2y=8-12 \\ 2y=-4 \\ \text{Divide both sides by 2} \\ \frac{2y}{2}=\frac{-4}{2} \\ y=-2 \end{gathered}[/tex]The solution to the linear system is x=3 and y=-2.
