The volume of a gas in a container varies inversely as the pressure on the gas. If a gas has a volume of 270 cubic inches under a pressure of 6 pounds per square inch, what will be its volume if the pressure is increased to 7 pounds per square inch? Round your answer to the nearest integer if necessary.

Respuesta :

If two quantities (V , P) are in inverse proportion, so

[tex]\begin{gathered} V=\frac{K}{P} \\ OR \\ \frac{V_1}{V_2}=\frac{P_2}{P_1} \end{gathered}[/tex]

You can use one of these two rules to solve your question

K is the constant of variation, you can find it by using the initial values

Let us use the second rule

When V = 270 cubic inches, P = 6 pounds/square inch

We need to find V = ?, P = 7 pounds/square inch

By using the second rule

[tex]\frac{270}{V_2}=\frac{7}{6}[/tex]

By using cross multiplication

[tex]\begin{gathered} 7V_2=270\times6 \\ 7V_2=1620 \end{gathered}[/tex]

Divide both sides by 7

[tex]\begin{gathered} \frac{7V_2}{7}=\frac{1620}{7} \\ V_2=231.429 \end{gathered}[/tex]

Round the answer to the nearest integers

[tex]V_2=231inch^3[/tex]

The volume of the gas is 231 cubic inches