hello
to solve this question, we should simply use trigonometric ratios SOHCAHTOA to determine which of the ratios to use
[tex]\begin{gathered} \text{soh}=\sin \theta=\frac{opp}{hyp} \\ cah=\cos \theta=\frac{adjacent}{hypothenus} \\ \text{toa}=\tan \theta=\frac{opposite}{adjacent} \end{gathered}[/tex]the diagram above is a representation of what we should reference to in terms of position of the sides in a triangle.
to find the length of BC, we have to use sine angle because we have the value of theta and hypothenus and we are solving for opposite
[tex]\begin{gathered} \sin \theta=\frac{opposite}{hypothenus} \\ \theta=27 \\ hyp=26 \\ \sin 27=\frac{BC}{26} \\ BC=26\times\sin 27 \\ BC=11.80 \end{gathered}[/tex]
from the calculation above, the length of line BC is equal to 11.80 units
