The two top concert tours in 2016 were concert A and concert B Based on iverage ticket prices, it cost a total of $1719 to purchase six tickets for concert A and ninetickets for concert B Four tickets for concert A and three tickets for concert B cost a total of 807 How much did an average ticket cost for each tour?

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Answer:

Step-by-step explanation:

Given the information, create a system of equations.

Let x be the cost of each ticket for concert A

Let y be the cost of each ticket for concert B

If it cost $1,719 to purchase six tickets for concert A and nine tickets for concert B.

[tex]6x+9y=1719\text{ \lparen1\rparen}[/tex]

If it cost $807 to purchase four tickets for A and three tickets for B.

[tex]4x+3y=807\text{ \lparen2\rparen}[/tex]

Isolate one of the variables, in this case ''x'' in one of the equations. Substitute x into the other equation.

Isolate x in (2).

[tex]\begin{gathered} x=\frac{807}{4}-\frac{3}{4}y \\ x=-\frac{3}{4}y+201.75 \end{gathered}[/tex]

Plug it into equation (1):

[tex]\begin{gathered} 6(-\frac{3}{4}y+201.75)+9y=1719 \\ -\frac{9}{2}y+1210.5+9y=1719 \\ 4.5y=1719-1210.5 \\ y=\frac{508.5}{4.5} \\ y=\text{ \$113} \end{gathered}[/tex]

Knowing the value of ''y'', substitute it into the equation (2):

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