Step 1
The reaction here is:
4 NaCl + CO2 => 2 Na2O+ CCl4 (Don't forget to balanced it)
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Step 2
Information provided:
The number of moles of carbon dioxide (CO2) = 0.89 moles
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Information needed:
The molar mass of Na2O = 62 g/mol approx.
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Step 3
By stoichiometry,
Procedure:
4 NaCl + CO2 => 2 Na2O+ CCl4
1 mole CO2 --------- 2 x 62 g Na2O
0.89 moles CO2 --------- X
X = (0.89 moles CO2 x 2 x 62 g Na2O)/1 mole CO2 = 110 g approx.
Answer: 110 g of Na2O produced.
