An object moving at a constant velocity of 5.4 m/s travels for 12 s.
How far will it move during that time?
Recall that the velocity, distance, and time are related as
[tex]\begin{gathered} v=\frac{s}{t} \\ s=v\cdot t \end{gathered}[/tex]Where s is the horizontal distance, v is the velocity, and t is the time.
Let us substitute the given values and find the distance (s)
[tex]\begin{gathered} s=5.4\cdot12 \\ s=64.8\; m \end{gathered}[/tex]Therefore, the object will move 64.8 m during 12 s.
