The prism net shown in the figure consists of 4 identical 3x1 rectangles and two 1x1 squares; therefore,
[tex]\begin{gathered} A_{rectangle}=3*1=3 \\ and \\ A_{square}=1*1=1 \end{gathered}[/tex]Thus,
[tex]A_{total}=4A_{rectangle}+2A_{square}=4*3+2*1=12+2=14[/tex]Hence, the surface area of the net is 14in^2