Answer:
Perimeter is 12+2√26
Step-by-step explanation:
Question:
The perimeter of quadrilateral PQRS with the vertices
P(-2, -2), Q(-1, 3), R(5, 3), and S(4, -2)
Find distances PS and QR:
Notice the y-coordinates are the same for 2 pairs of points
P(-2, -2), S(4, -2) and Q(-1, 3), R(5, 3)
So the distance PS = |-2|+4= 6 and QR = |-1|+5 = 6
Find the distances PQ and SR:
Use the distance formula:
[tex]d= \sqrt{(x_{2}-x_{1} ) ^{2} + (y_{2}-y_{1} ) ^{2} }[/tex]
P([tex]x_{1}[/tex] = -2, [tex]y_{1}[/tex] = -2), Q( [tex]x_{2}[/tex] = -1, [tex]y_{2}[/tex] = 3)
PQ = [tex]\sqrt{(-1--2)^{2} +(3- -2)^{2} } = \sqrt{1^{2} +5^{2} } = \sqrt{26}[/tex]
SR = [tex]\sqrt{26}[/tex], because of PQ and SR are equal.
Find the perimeter of quadrilateral PQRS:
The perimeter is equal to the sum of all sides of the quadrilateral.
P= PS + QR + PQ + SR = 6+6+ √26 +√26 = 12+2√26
