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The braking distance traveled by the car is 73.5 m.

What is the braking distance of the car?

The braking distance traveled as the speed of the car is reduced from 21 m/s to 0m/s​ at a deceleration rate of 3 m/s² is calculated as follows.

v² = u² - 2as

where;

  • v is the final velocity of the car, when it stops = 0
  • u is the initial velocity of the car = 21 m/s
  • a is the deceleration of the car = 3 m/s²
  • s is the braking distance of the car

Substitute the given parameters and solve for the braking distance of the car as shown below.

0 = u² - 2as

2as = u²

s = (u²) / (2a)

s = (21²) / (2 x 3)

s = 73.5 m

Learn more about braking distance here: https://brainly.com/question/4085091

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The complete question is below:

calculate the braking distance traveled as the speed of the car is reduced from 21 m/s to 0m/s​, when the car is decelerating at 3 m/s².

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