when three positive integers $a, b$, and $c$ are multiplied together, their product is $100$. suppose $a < b < c$. in how many ways can the numbers be chosen?

Respuesta :

Together the numbers a , b and c can be chosen in 4 ways.

Given:

when three positive integers $a, b$, and $c$ are multiplied together, their product is $100$ and a < b < c .

The positive divisors of 100 are :

1 , 2 , 4 , 5 , 10 , 20 , 25 , 50 , 100.

It is clear that :

10 ≤ c ≤ 50.

so we apply from c value 10.

if c = 10 ,  then ( a , b , c ) = ( 2 , 5 , 10 )

if c = 20 ,  then ( a , b , c ) = ( 1 , 5 , 10 )

if c = 25 ,  then ( a , b , c ) = ( 1 , 4 , 25 )

if c = 50 ,  then ( a , b , c ) = ( 1 , 2 , 50 )

we can observe ways = 4.

Therefore the number of ways is 4.

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