The rounded upper level of the 68% confidence interval estimate is
164.5 ± 3.260.
Given:
a cheese merchant looks a again at the data set about total cheese of sales, in which the sample mean is 164.5 and the sample of standard deviation is 103.
μ = x =164.5
σ = s = 103
n = 987
z score at 68 % :
= 0.9945
Confidence interval CI = x + z * s/[tex]\sqrt{n}[/tex]
= 164.5 + 0.9945 * 103 / √987
= 164.5 ± 3.260
Therefore The rounded upper level of the 68% confidence interval estimate is 164.5 ± 3.260.
Learn more about the confidence interval here:
https://brainly.com/question/24131141
#SPJ4