mandylewis6789 mandylewis6789

01-03-2017
Mathematics

contestada

How many three-digit numbers greater than 200 can be formed from the digits 1, 2, 6, 7, and 9, if the digits can be repeated?

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siegman29 siegman29

01-03-2017

. You have four choices for the first digit (2,6,7 or 9) because if the first digit is one, the number will be less than 200. You have five choices each for the second and third digit. 4*5*5=100 possible numbers.

2. This is simply 10C3=(10*9*8)/(3*2*1)=120.

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hiiamshyan hiiamshyan

04-03-2017

12 for each so 12x5=60

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