Answer : The molarity of a solution is, 1.84 M
Explanation : Given,
Mass of [tex]Na_2SO_4[/tex] = 85.0 g
Molar mass of [tex]Na_2SO_4[/tex] = 142 g/mole
Volume of solution = 325 ml
Molarity : It is defined as the number of moles of solute present in one liter of solution.
In this question, the solute is [tex]Na_2SO_4[/tex].
Formula used :
[tex]Molarity=\frac{w_b}{M_b\times V}\times 1000[/tex]
where,
[tex]w_b[/tex] = mass of solute [tex]Na_2SO_4[/tex]
[tex]M_b[/tex] = molar mass of solute [tex]Na_2SO_4[/tex]
[tex]V[/tex] = volume of solution in ml
Now put all the given values in the above formula, we get the molarity of the solution.
[tex]Molarity=\frac{85.0g}{142g/mole\times 325ml}\times 1000=1.84mole/L=1.84M[/tex]
Therefore, the molarity of the solution is, 1.84 M
