A light bulb, a fan, and a tiny speaker are connected to a battery in a series circuit. How will the circuit behave if it is open?

A) None of the devices will work.
B) The battery will heat up and explode.
C) Only the device closest to the battery will work.
D) The bulb will light, the fan will blow, and the speaker will make noise.

Question

03-03-2017
Physics

contestada

A light bulb, a fan, and a tiny speaker are connected to a battery in a series circuit. How will the circuit behave if it is open?

A) None of the devices will work.
B) The battery will heat up and explode.
C) Only the device closest to the battery will work.
D) The bulb will light, the fan will blow, and the speaker will make noise.

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AL2006 AL2006 · Answer 1 · 2017-03-03T01:49:12+01:00

AL2006 AL2006

03-03-2017

If the circuit is open, then no current flows, and none of the devices does anything. They all just lay there, stone cold.

Answer Link

Branta Branta · Answer 2 · 2019-03-26T07:09:48+01:00

Answer: The correct option is A.

Explanation:

In the given problem, a light bulb, a fan, and a tiny speaker are connected to a battery in a series circuit. But the circuit is open.

The battery forces the electrons to flow in the circuit. The rate of flow of electrons constitutes the current. But the battery is not on. Then , the current will not flow in the circuit.

Therefore, None of the devices connected in the circuit will work.