Respuesta :
Your answer is 12.3 kJ. The molor heat of fusion kind of tells you A thing about it. I hope I could help! :)
Have a wonderful rest of the day.
Have a wonderful rest of the day.
Answer : The correct option is, (B) 12.3 KJ
Solution :
First we have to calculate the moles of water.
[tex]\text{Moles of water}=\frac{\text{Mass of water}}{\text{Molar mass of water}}=\frac{36.8g}{18g/mole}=2.04mole[/tex]
Now we have to calculate the amount of heat released.
Formula used :
[tex]q=n\times \Delta H_{fusion}[/tex]
where,
q = heat released
n = number of moles = 2.04 mole
[tex]\Delta H_{fusion}[/tex] = molar enthalpy of fusion of a substance = -6.01 KJ/mole
Now put all the give values in the above formula, we get the amount of heat released.
[tex]q=(2.04mole)\times (-6.01KJ/mole)=-12.3KJ[/tex]
The negative sign indicate heat released.
Therefore, the amount of heat released is, 12.3 KJ