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pkmnmushy
You need to have in mind the following equations given two different notations: 
In Organic notation you write the lacti acid calculation like this: 
CH3CH(OH)COOH(aq) <----> CH3CH(OH)COOH-(aq) + H+ (aq) 
Now the simplified formula equation will be: 
HC3H5O3(aq) <-----> H+(aq) + C3H5O3(aq) 
0.110 - x M .................. x M ............. x M 
havign the regular formula you proceed as follows:
Ka = [H+] [C3H5O3] / [HC3H5O3] 
1.4x10^-4 = (x)(x) / (0.110 - x)
Do the maths and you will get the answer.  

Answer:

3.57

Explanation:

Ka = ca2

==> a = √ ( Ka / c )

Given Ka = 1.4x10^-4

         c = concentration = 0.110 M

Plug the values we get a = 0.0357

% dissociation = 0.0357 x 100 = 3.57

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