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Typically, a bullet leaves a standard .50-caliber rifle (29.0-in. barrel) at a speed of 853 m/s. If it takes 1.2 milliseconds to traverse the barrel, determine the average acceleration experienced by the 49.0-gram bullet within the gun amd then compute the average force exerted on it.

Respuesta :

noahmmackay
To find what a is, consider the equation v=at (v=velocity, a=acceleration, t=time interval), making a=v/t. Take the given v of 853m/s, and divide that by your time IN SECONDS, so 1.2ms=1.2*10^-3s.

a=(853)/(1.2*10^-3)=7.11*10^5 m/s^2.

Now Having F=ma, where a is your acceleration, and m=mass (which is 49*10^-3 kg),

F=(49*10^-3)(7.11*10^5)=3.48*10^4 N

Hope this helps!

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