Respuesta :
moles of N20 is: 82/(14*2+16)= 1.86 (moles)
In N2O there are 2 nitrogen so moles of nitrogen will be: 1.86 * 2 = 3.72 (moles)
In N2O there are 2 nitrogen so moles of nitrogen will be: 1.86 * 2 = 3.72 (moles)
Answer : The number of moles of nitrogen present in nitrous oxide are 3.72 moles.
Explanation : Given,
Mass of = 82.0 g
Molar mass of [tex]N_2O[/tex] = 44 g/mole
First we have to calculate the moles of [tex]N_2O[/tex].
[tex]\text{ Moles of }N_2O=\frac{\text{ Mass of }N_2O}{\text{ Molar mass of }N_2O}=\frac{82.0g}{44g/mole}=1.86moles[/tex]
Now we have to calculate the moles of nitrogen in nitrous oxide.
In nitrous oxide [tex]N_2O[/tex], there are 2 moles of nitrogen and 1 mole of oxygen.
As, 1 moles of [tex]N_2O[/tex] contains 2 moles of nitrogen
So, 1.86 moles of [tex]N_2O[/tex] contains [tex]1.86\times 2=3.72moles[/tex] of nitrogen
Therefore, the number of moles of nitrogen present in nitrous oxide are 3.72 moles.