Answer:
The solution are -2 + √10 and -2 - √10
Step-by-step explanation:
When we solve a quadratic equation by completing the square method,
We follow the following steps,
Step 1 : Move the constant term to the right side,
Step 2 : Make 1 as the coefficient of [tex]x^2[/tex]
Step 3 : Add the square of half of the coefficient of x on both sides.
Here, the given quadratic equation,
[tex]2x^2 + 8x - 12 = 0[/tex]
By above steps,
[tex]2x^2+8x=12[/tex]
[tex]\frac{2}{2}x^2+\frac{8x}{2}=\frac{12}{2}[/tex]
[tex]x^2+4x=6[/tex]
Half of 4 = 2
Square of 2 = 4
So, add 4 on both sides,
[tex]x^2+4x+4=6+4[/tex]
[tex](x+2)^2=10[/tex]
[tex]x+2=\pm \sqrt{10}[/tex]
[tex]\implies x = -2\pm\sqrt{10}[/tex]
Hence, the solution are -2 + √10 and -2 - √10
