The radius of the circle whose equation is (x - 3)² + (y + 1)² = 16 is:
4 units.
We know that the general equation of a circle with center at (h,k) and radius 'r' is represented by the equation:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
Here we are given a equation as:
[tex](x-3)^2+(y+1)^2=16[/tex]
i.e. on comparing the given equation with the general equation we have
h=3 and k= -1
and [tex]r^2=16[/tex]
on taking square root we get:
[tex]r=4[/tex]
Hence, the radius of the equation is:
4 units
