What is the value of x? Round your answer to the nearest tenth if necessary.




Right triangle whose two legs measure fourteen and x, and whose hypotenuse measures twenty

Respuesta :

x is equal to 1.2, I think.
To solve this we'll use Pythagorean theorem.
Which is a^2+b^2=c^2

C is the hypotenuse, and a or b can be either leg.
Because we start with the hypotenuse we rearrange the equation to be c^2-a^2= b^2

-A and B are universal, so you can plug them into either one-

So
20^2-14^2=b^2
Take note that b is raised to the 2nd power
So in order to undo it we'll square root it

To solve this we'll use Pythagorean theorem.
Which is a^2+b^2=c^2

C is the hypotenuse, and a or b can be either leg.
Because we start with the hypotenuse we rearrange the equation to be c^2-a^2= b^2

-A and B are universal, so you can plug them into either one-

So
20^2-14^2=b^2
Take note that b is raised to the 2nd power
So in order to undo it we'll square root it


√(204=14.282856857
We then go to the tenth place, So the answer is rounded to 14.3

X=14.3