What is the equation for the linear model in the scatter plot obtained by choosing the two points closest to the line?
A)Y = -3 x+ 56
B)Y = -2 x +46
C)Y = -2 x +56
D)Y = 2 x + 56

What is the equation for the linear model in the scatter plot obtained by choosing the two points closest to the line AY 3 x 56 BY 2 x 46 CY 2 x 56 DY 2 x 56 class=

Respuesta :

The best choice would probably be C. We know the y-intercept is higher than 46 and that the slope is negative. That leaves us with choice A and C. We can eliminate A because when using the slope formula, the answer is closer to 2 than 3. However, even though it's most likely C, I would check first.

Answer:

Option C is the answer.

Step-by-step explanation:

To find the equation of the straight line equation i.e, we must be given with the two points [tex]\left (x_{1},y_{1} \right )[/tex] and [tex]\left (x_{2},y_{2}\right )[/tex]

Since from the graph the two points closest to the line are[tex]\left ( 10,36 \right )[/tex] and [tex]\left ( 22,12 \right ).[/tex]

Equation of line with two points closest to the line :

                                                    [tex]y-y_{1}=m\cdot \left ( x-x_{1} \right )[/tex]

where m is the slope.

First we find the slope(m)=[tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]  

[tex]m=\frac{12-36}{22-10}[/tex]

on simplify we get,  [tex]m=-2[/tex].

Now, to find  the equation of the line:  [tex]y-y_{1}=m\cdot \left ( x-x_{1} \right )[/tex]

[tex]y-36=\left ( -2 \right )\cdot \left ( x-10 \right )[/tex]

Apply distributive property on right hand side, we get

[tex]y-36=-2\cdot x+20[/tex]

Adding both sides by 36, we get

[tex]y=-2x+20+36[/tex]

[tex]y=-2x+56[/tex].

The equation for the linear  model in the scatter plot obtained by the two closest point [tex]\left ( 10,36 \right ) and \left ( 22,12 \right )[/tex] closest to the line is,

[tex]y=-2x+56[/tex]