Respuesta :
y=mx+b, where m=(y2-y1)/(x2-x1) and b is equal to the value of y when x=0
We are given the point (0,0) so we know b=0, now just find the slope...
m=(-3-0)/(4-0)=-3/4 so the line is:
y=-3x/4
We are given the point (0,0) so we know b=0, now just find the slope...
m=(-3-0)/(4-0)=-3/4 so the line is:
y=-3x/4
we have that
The line passes through the points [tex]A(0,0)\ B(4,-3)[/tex]
If the point passes through the origin
then
The linear equation is a direct variation
Remember that
A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form [tex]y/x=k[/tex] or [tex]y=kx[/tex]
In this case the constant of proportionality k is equal to the slope of the line
Find the value of k
[tex]y/x=k[/tex]
Substitute the values of x and y of the point B
[tex]-3/4=k[/tex]
[tex]k=-\frac{3}{4}[/tex]
the equation of the line is
[tex]y=-\frac{3}{4}x[/tex]
therefore
the answer is
[tex]y=-\frac{3}{4}x[/tex]