How many extraneous solutions does the equation below have?
9/(n^2+1)=(n+3)/4
0
1
2
3

Question

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Respuesta :

smmwaite smmwaite · Answer 1 · 2018-11-10T19:35:57+01:00

Answer

0

Explanation

9/(n²+1)=(n+3)/4

9/(n²+1) = (n+3)/4

(9 × 4)/(n²+1) = n+3

36/(n² + 1) = (n + 3)

36 = (n²+1)(n+3)

36 = n³+3n²+n+3

n³ + 3n² + n - 33 = 0

This is a cubic function and so, it have 3 solutions.

No extraneous solutions.

Answer Link

abidemiokin abidemiokin · Answer 2 · 2022-04-25T17:54:13+02:00

The resulting equation has a leading degree of 3, hene the equation will have 3 solution with NO extraneous solutions

Extraneous solutions can also be inferred as the non-real solution of an equation. Given the equation expressed as:

9/(n^2+1)=(n+3)/4

Cross multiply

n^2+1(n+3) = 4(9)
n^3 + 3n^2 + n + 3 = 36
n^3 + 3n^2 +n - 33 = 0

Since the resulting equation has a leading degree of 3, hence the equation will have 3 solution with NO extraneous solutions

Learn more on extraneous solution here: https://brainly.com/question/2959656