A point charge of 6.8 C moves at 6.5 × 104 m/s at an angle of 15° to a magnetic field that has a field strength of 1.4 T.
What is the magnitude of the magnetic force acting on the charge?

a. 1.6 × 10^–1 N
b. 6.0 × 10^–1 N
c. 1.6 × 10^5 N
d. 6.0 × 10^5 N

Respuesta :

the answer is A on Edge

The magnitude of the magnetic force acting  on the charge is                1.6 × 10⁵ N.

To find the magnitude of the magnetic force acting on the charge is given as, q = 6.8 C

v = 6.5 × 10⁴ m/s

angle = 15°

B = 1.4 T.

Define Lorentz Force. write the formula and how it gets solved.

The magnetic field exerts a force on a moving charged particle is said to be Lorentz force. The value of the force depends on the charge,  velocity, magnetic field and the angle. The direction of the Lorentz force is perpendicular for both the particle direction and to the magnetic field.

  Formula can be written as,

                              F = q v B sin(α)

where,

q - particle's charge,

v - particle's velocity,

B - strength of the magnetic field,

α  - angle between the direction of the particle's trajectory and the direction of the magnetic field,

F - resulting force.

Substituting all the values,

                       F = ( 6.8 × 6.5 × 10 ⁴ m/s × 1.4 × sin ( 15°))

                         = 60.928 × 0.25881 × 10 ⁴

                        F = 1.6 × 10⁵ N.

Hence, option C is the correct answer.    

Learn more about the Lorentz force,

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