Respuesta :
1)a
2)5
3)Population size:11
Lower quartile (xL): 45
Upper quartile (xU): 60
Interquartile range (xU-xL): 15
2)5
3)Population size:11
Lower quartile (xL): 45
Upper quartile (xU): 60
Interquartile range (xU-xL): 15
1) Mean of {21, 23, 25, 25, 26, 28, 28, 28, 31, 33}
Mean = (21+23+25+25+26+28+28+28+31+33)/10 = 26.8
2) Average of the 12 flowers = 4 days
Average of the 4 remaining flowers = 6 days
Average of these 2 averages is (4+6)/2 = 10/2 = 5days
3) IQR of {48, 50, 65, 60, 80, 42, 45, 50, 42, 55, 45}
To find the Inter Quartile Range, you have to:
a) Order data set from smaller to higher:
[42,42,45,45,48,50,50,55,60,65,80}
b) Find the Median (central value) of the set: Tat is 50 (this is called Q2), which is the Median
c) Split data on the left of the first 50, into half, the median of this half is 45
This is called Q1 =45 (first quartile)
d) Split data on the right of the first 50, into half, the median of this half is 60
This is called Q3 = 60 (3rd quartile)
Now to find the Inter Quartile Range we have to subtact Q1 from Q3:
IQR = Q3 - Q1 = 60 - 45 = 15
Mean = (21+23+25+25+26+28+28+28+31+33)/10 = 26.8
2) Average of the 12 flowers = 4 days
Average of the 4 remaining flowers = 6 days
Average of these 2 averages is (4+6)/2 = 10/2 = 5days
3) IQR of {48, 50, 65, 60, 80, 42, 45, 50, 42, 55, 45}
To find the Inter Quartile Range, you have to:
a) Order data set from smaller to higher:
[42,42,45,45,48,50,50,55,60,65,80}
b) Find the Median (central value) of the set: Tat is 50 (this is called Q2), which is the Median
c) Split data on the left of the first 50, into half, the median of this half is 45
This is called Q1 =45 (first quartile)
d) Split data on the right of the first 50, into half, the median of this half is 60
This is called Q3 = 60 (3rd quartile)
Now to find the Inter Quartile Range we have to subtact Q1 from Q3:
IQR = Q3 - Q1 = 60 - 45 = 15