Respuesta :
Very low :)
P(HHHHH)=(1/2)(1/2)(1/2)(1/2)(1/2)
P(HHHHH)=(1/2)^5
P(HHHHH)=1/32 (3.125%)
P(HHHHH)=(1/2)(1/2)(1/2)(1/2)(1/2)
P(HHHHH)=(1/2)^5
P(HHHHH)=1/32 (3.125%)
Answer:
[tex]\frac{1}{32}[/tex] or 0.03
Step-by-step explanation:
Probability of getting head for a single coin toss = [tex]\frac{number of heads}{number of possible outcomes}[/tex]
=[tex]\frac{1}{2}[/tex]
Probability of getting head for five simultaneous coin toss = [tex]\frac{1}{2} * \frac{1}{2} * \frac{1}{2} * \frac{1}{2} * \frac{1}{2}[/tex]
= [tex]\frac{1}{32}[/tex]
= 0.03 [converted into a decimal]