Respuesta :

irspow
Very low :)

P(HHHHH)=(1/2)(1/2)(1/2)(1/2)(1/2)

P(HHHHH)=(1/2)^5

P(HHHHH)=1/32  (3.125%)

Answer:

[tex]\frac{1}{32}[/tex] or 0.03

Step-by-step explanation:

Probability of getting head for a single coin toss = [tex]\frac{number of heads}{number of possible outcomes}[/tex]

=[tex]\frac{1}{2}[/tex]

Probability of getting head for five simultaneous coin toss = [tex]\frac{1}{2} * \frac{1}{2} * \frac{1}{2} * \frac{1}{2} * \frac{1}{2}[/tex]

= [tex]\frac{1}{32}[/tex]

= 0.03 [converted into a decimal]