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Two carts collide and bounce apart. Cart 1 had a momentum of –6 kg • m/s before the collision. Cart 2 had a momentum of 10 kg • m/s before the collision. What is the total momentum of the carts after the collision?

Respuesta :

Two carts belong to the same system. Since, the there is no external force on the system during the collision, the momentum of the system will conserved as the internal forces which are acting during the collision cannot change the momentum of the system.

Hence, Initial momentum of the system = Final momentum of the system

Initial momentum = - 6 + 10 = 4 kg m/s

Hence, the total momentum of the carts after the collision = 4 kg m/s

The initial collision of the two body is equal to the final collision of two bodies by the law of conservation of momentum.

The total momentum of the carts after the collision is 4kg-m/s.

What is conservation of momentum?

Momentum of a object is the force of speed of it in motion. Momentum of a moving body is the product of mass times velocity.

When the two objects collides, then the initial collision of the two body is equal to the final collision of two bodies by the law of conservation of momentum.

Given information-

The momentum of the cart one before the collision is -6 kg-m/s.

The momentum of the cart two before the collision is 10 kg-m/s.

The total initial momentum of the cart one and two before the collision is,

[tex]p_1=-6+10\\p_1=4\rm kg-m/s[/tex]

Thus the total initial momentum of the cart one and two before the collision is 4 kg-m/s.

As the initial collision of the two body is equal to the final collision of two bodies by the law of conservation of momentum.

Thus, the  total momentum of the carts after the collision is,

[tex]p_f=p_i\\p_f=4kg-m/s[/tex]

Hence the total momentum of the carts after the collision is 4kg-m/s.

Learn more about the conservation of momentum here;

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