so.. hmm check the picture below
now, to know where A and B are, that occurs when the parabolic equation equates the linear one
thus
[tex]\bf y=-2x^2+8x
\\\\\\
x-2.23y+10.34=0\implies \cfrac{x+10.34}{2.23}=y
\\\\\\
y=y\implies -2x^2+8x=\cfrac{x+10.34}{2.23}
\\\\\\
-4.46x^2+17.84x=x+10.34
\\\\\\
0=4.46x^2-16.84x+10.34[/tex]
now, running that on the quadratic formula, you end up with the values of 3.00402497440839842242 and 0.77175977895483027713
thus B rounded up is 3.004 and A rounded up is 0.7718
what's the "y" value for B?, well, you can use either the linear or quadratic equation for that, let's use the quadratic one
[tex]\bf B=3.00402497440839842242
\\\\\\
f(B)=-2B^2+8B\implies f(B)=5.98386770152842978586[/tex]
