Respuesta :
we need to use the following formula
Δ[tex]G= -nF E_{cell} [/tex]
[tex]E_{cell}= 0.24V[/tex]
n= 4 moles
F= constant= 96500C/mol
let's plug in the values.
ΔG= -(4)(96500)(0.24)= -92640 J or -92.6 kJ
Δ[tex]G= -nF E_{cell} [/tex]
[tex]E_{cell}= 0.24V[/tex]
n= 4 moles
F= constant= 96500C/mol
let's plug in the values.
ΔG= -(4)(96500)(0.24)= -92640 J or -92.6 kJ
Step 1. Use ∆G = -nFEo.
Step 2. Plug in n = 4, F = 96,500 and E = +0.24
Step 3. ∆G = -4 × 96,500 × 0.24 = -92,640 J = -92.64 kJ.