Respuesta :
I've answered this question before. By the way, here is the box plot for this problem, please see attached image.
He should visit Orlando. The median is higher and the range is smaller, so the temperature is higher on average. This is the correct answer, as we are only interested in the average temperature in both cities in deciding which to go to. The larger the range (max - min values) or interquartile range (range of central box), the more spread out the temperatures are around the median. As Orlando's range and interquartile range is lower than Tampa Bay's, and its median (middle value in the data set of temperatures) is higher, Dominick would, on average, have more chance of visiting Orlando on a day when it was warmer than Tampa Bay than the other way around.
He should visit Orlando. The median is higher and the range is smaller, so the temperature is higher on average. This is the correct answer, as we are only interested in the average temperature in both cities in deciding which to go to. The larger the range (max - min values) or interquartile range (range of central box), the more spread out the temperatures are around the median. As Orlando's range and interquartile range is lower than Tampa Bay's, and its median (middle value in the data set of temperatures) is higher, Dominick would, on average, have more chance of visiting Orlando on a day when it was warmer than Tampa Bay than the other way around.
Answer:
the second option
Step-by-step explanation:
i took the test :) hope this helps!!!