Dielectric materials used in the manufacture of capacitors are characterized by conductivities that are small but not zero. therefore, a charged capacitor slowly loses its charge by "leaking" across the dielectric. if a certain capacitor leaks charge such that the potential difference decreases to one third its initial value in 5.60 s, what is the equivalent resistance of the dielectric? round your answer to three significant figures.

Respuesta :

You need to know the capacitance of the capacitor, C.

The voltage after time t is equal to the original voltage times e^(t/RC) where R is the resistance that you are trying to find.