We first need to standardise the value X=50 and X=62, in other words, find the z-scores.
The formula to find z-score is (X-μ)/σ
Where μ is the mean score which in this case is 50 and σ is the standard deviation = 6
Z-score for X = 50 ⇒ (50-50)÷6 = 0÷6 = 0
Z-score for X = 62 ⇒ (62-50)÷6 = 12÷6 = 2
Presenting this information on a normal distribution bell curve, the area we need is in between z = 0 and z = 2
P(0<z<2) = P(z<2) - P(z<0)
P(0<z<2) = 0.9772 - 0.5
P(0<z<2) = 0.4772
As a percentage, the probability is 0.4772 × 100 = 47.72%
