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The values that a discrete random variable, x, can take are 1,2,3,4 with the probabilities 0.22, 0.19, 0.38, 0.21 respectively. What is the expected value of this discrete probability distribution?
a. 2.78
b. 3.42
c. 2.15
d. 4.01

Respuesta :

Answer:

E(x) = .22(1) + .19(2) + .38(3) + .21(4)

= .22 + .38 + 1.14 + .84

= 2.58

None of those choices are correct.

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