Answer:
the specific heat capacity of the liquid is approximately 517.07 J/kgK.
Explanation:
To calculate the specific heat capacity of the liquid, we can use the principle of conservation of energy.
First, let's calculate the heat lost by the brass as it cools down. The heat lost can be calculated using the formula:
heat lost = mass of brass * specific heat capacity of brass * change in temperature
mass of brass = 300 grams = 0.3 kg
specific heat capacity of brass = 380 J/kgK
change in temperature = (950 - 100) degrees Celsius = 850 degrees Celsius = 850 K
heat lost = 0.3 * 380 * 850 = 97,300 J
Next, let's calculate the heat gained by the liquid as it warms up. The heat gained can be calculated using the formula:
heat gained = mass of liquid * specific heat capacity of liquid * change in temperature
mass of liquid = 250 grams = 0.25 kg
specific heat capacity of liquid = unknown (to be calculated)
change in temperature = (100 - 25) degrees Celsius = 75 degrees Celsius = 75 K
heat gained = 0.25 * specific heat capacity of liquid * 75
Since the heat lost by the brass is equal to the heat gained by the liquid (assuming no heat loss to the surroundings), we can set up an equation:
97,300 = 0.25 * specific heat capacity of liquid * 75
Now, let's solve for the specific heat capacity of the liquid:
specific heat capacity of liquid = 97,300 / (0.25 * 75)
specific heat capacity of liquid = 517.07 J/kgK
Therefore, the specific heat capacity of the liquid is approximately 517.07 J/kgK.
