Answer:
D) 0.1
Step-by-step explanation:
Probability:
The sum of all the outcomes of the given event is 1.
P(E1) + P(E2) + P(E3) + P(E4) = 1
0.2 + 0.3 + 0.4 +P(E4) = 1
0.9 + P(E4) = 1
P(E4) = 1 - 0.9
P(E4) = 0.1
To find the probability of the fourth outcome (P(E4)) in an experiment with P(E1) = 0.2, P(E2) = 0.3, and P(E3) = 0.4, subtract the sum of these probabilities from 1; P(E4) = 1 - (0.2 + 0.3 + 0.4) = 0.1.
The question asks to determine the probability of the fourth outcome (P(E4)) given the probabilities of the first three outcomes in an experiment. The probabilities of the first three outcomes are P(E1) = 0.2, P(E2) = 0.3, and P(E3) = 0.4. Since the total probability of all outcomes must equal 1 in a probability distribution, we can calculate P(E4) by subtracting the sum of the given probabilities from 1.
The calculation is as follows:
P(E4) = 1 - (P(E1) + P(E2) + P(E3))
P(E4) = 1 - (0.2 + 0.3 + 0.4)
P(E4) = 1 - 0.9
P(E4) = 0.1
Therefore, the correct answer for P(E4) is 0.1 (option d).
