let's say the angles are "a", "b" and "c"
[tex]\bf \begin{cases}
\stackrel{first}{a}\\
\stackrel{second}{b}=\stackrel{\textit{2 less than 3 times \underline{a}}}{3a-2}\\
\stackrel{third}{c}=\stackrel{\textit{14 more than twice \underline{a}}}{2a+14}
\end{cases}
\\\\\\
\textit{now, the sum of all internal angles in a triangle is }180^o
\\\\\\
a+b+c=\implies a+(3a-2)+(2a+14)=180
\\\\\\
6a+12=180\implies 6a=180-12\implies 6a=168\implies a=\cfrac{168}{6}
\\\\\\
a=28[/tex]
so a = 28°, plug that in "b" and "c", to see how much each is.
