Respuesta :
D. distribute the 3 to each term in the parentheses by multiplying.
3(2x - 6 - x - 1)^2 - 2 + 4x
3(x-7)^2 - 2 + 4x
3 (x^2 -14x +49) - 2 + 4x
3x^2 - 42x + 147 - 2 + 4x
3(2x - 6 - x - 1)^2 - 2 + 4x
3(x-7)^2 - 2 + 4x
3 (x^2 -14x +49) - 2 + 4x
3x^2 - 42x + 147 - 2 + 4x
Answer:
Distribute the 3 to each term in the parentheses by multiplying.
Step-by-step explanation:
3(2x – 6 – x + 1)^2 – 2 + 4x
In Step 1 she simplified within the parentheses.
The expression becomes [tex]3(x-5)^2 - 2 + 4x[/tex]
In Step 2 she expanded the exponent.
After expanding the exponent (x-5)^2 it becomes (x^2-10+25)
[tex]3(x^2-10+25) - 2 + 4x[/tex]
In the next step we distribute 3 inside the parenthesis in order to remove the parenthesis .
Answer: Distribute the 3 to each term in the parentheses by multiplying.