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Find the midpoint of the line segment whose endpoints are (0, 1/2) and (0, 3/4). (0, 2/3) (0, 5/8) (0, 1 1/4)

Respuesta :

[tex]A\ midpoint\ of\ the\ segment\ AB\ where\ A(x_A;\ y_A)\ and\ B(x_B;\ y_B):\\\\M_{AB}\left(\frac{x_A+x_B}{2};\ \frac{y_A+y_B}{2}\right)\\-----------------------\\\\A(0; \frac{1}{2})\to x_A=0\ and\ y_A=\frac{1}{2}\\\\B(0;\ \frac{3}{4})\to x_B=0\ and\ y_B=\frac{3}{4}\\\\therefore\\\\M_{AB}\left(\frac{0+0}{2};\ \frac{\frac{1}{2}+\frac{3}{4}}{2}\right)=\left(\frac{0}{2};\ \frac{\frac{1\cdot2}{2\cdot2}+\frac{3}{4}}{2}\right)=\left(0;\ \frac{\frac{2}{4}+\frac{3}{4}}{2}\right)[/tex]

[tex]=\left(0;\ \frac{\frac{2+3}{4}}{2}\right)=\left(0;\ \frac{\frac{5}{4}}{2}\right)=\left(0;\ \frac{5}{4}:2\right)=\left(0;\ \frac{5}{4}\cdot\frac{1}{2}\right)=\boxed{\left(0;\ \frac{5}{8}\right)}[/tex]

Answer:

(0, 5/8)

Step-by-step explanation:

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