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The total power input to a pumped storage power station is 600 MW
The useful power output is 540 MW calculate the efficiency of this pumped storage power station

Respuesta :

ayyTimmy
efficiency = (output / input) x 100
Efficiency = 54000/600 
efficiency = 90%
Cricetus

The efficiency of this pumped storage power station will be "90%".

The given values are:

Total Input power,

  • I = 600 MW

Output power,

  • O = 540 MW

As we know the formula,

→ [tex]Efficiency = \frac{O}{I}\times 100[/tex]

By substituting the values, we get

→                     [tex]= \frac{540}{600}\times 100[/tex]

→                     [tex]= \frac{540}{6}[/tex]

→                     [tex]= 90[/tex] (%)

Thus the above answer is appropriate.  

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https://brainly.com/question/14313112

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