Solve for x.
a(5 - x) = bx - 8

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pinquancaro pinquancaro · Answer 1 · 2018-10-17T12:47:03+02:00

Consider the given equation:

[tex]a(5-x)=bx-8[/tex]

We have to solve the given equation for the value of 'x', we get

We will use distributive property which states [tex]a(b+c) = ab+ ac[/tex]

[tex](a \times 5)+(a \times -x) = bx-8[/tex]

[tex]5a-ax = bx -8[/tex]

Equating the like terms and the constants, we get

[tex]5a+8= ax+bx[/tex]

Taking 'x' common from the RHS of the equation.

[tex]5a+8 = x(a+b)[/tex]

[tex]x = \frac{5a+8}{a+b}[/tex]

Therefore, the value of 'x' is [tex]x = \frac{5a+8}{a+b}[/tex].

swapnalimalwadeVT swapnalimalwadeVT · Answer 2 · 2022-05-03T11:18:17+02:00

The value of 'x' in equation a(5 - x) = bx - 8 is x=5a+8/(b+a).

Consider the given equation

a(5-1)=bx-8

We have to solve the given equation for the value of 'x', we get

We will use distributive property which states

a(b+c)=ab+ac

5a-ax=bx-8

Equating the like terms and the constants, we get

5a+8=bx+ax

Taking 'x' common from the RHS of the equation.

5a+8=x(b+a)

x=5a+8/(b+a)

Therefore, the value of 'x' is x=5a+8/(b+a).

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