lortiz1125
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I need help on how to figure out this question! A track coach made a two way table to show his runners gender and running category. Male: Sprints- 16 Middle distance- 11 Long distance- 9 Female: Sprints- 12 Middle distance- 14 Long distance- 5 To the nearest hundredth, what is the probability that a randomly chosen female runs sprints? This obviously says that order doesn't matter as they mention "randomly chosen". I am just having trouble figuring out how to solve this.

Respuesta :

There are 12 out of 31 females = .39

Answer: Approx 0.39 will be the required probability.

Step-by-step explanation:

Here,Number of,

Male: Sprints=16, Middle distance=11, Long distance= 9

So, total males=36

And, Female: Sprints= 12, Middle distance=14, Long distance=5

So, total females=31

Thus, If one female randomly chosen,

Then, The probability that female runs sprint= Number of females who run sprint / total number of females

⇒ The probability that female runs sprint=12/31= 0.38709677419≈0.39


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