Answer: Value of cos(M) is
[tex]\cos M=\frac{19}{20}[/tex]
Step-by-step explanation:
Since we have given that
LMN is a right angled triangle where L and M are complementary angles ,
And,
[tex]\sin L=\frac{19}{20}=\frac{Perpendicular}{Hypotenuse}[/tex]
so, we will find base now by using "Pythagorus theorem":
[tex]H^2=B^2+P^2\\\\20^2=B^2+19^2\\\\400=B^2+361\\\\400-361=B^2\\\\39=B^2\\\\\sqrt{39}=B[/tex]
As we know that side opposite to mentioned theta is considered as perpendicular as shown in the figure ,
For M as [tex]\theta[/tex]
NL will be its perpendicular and MN will be its base and to find the cos(M) we use Base and Hypotenuse.
So, now we will find cos(M) i.e.
[tex]\cos M=\frac{Base}{Hypotenuse}=\frac{19}{20}[/tex]
Hence,
[tex]\cos M=\frac{19}{20}[/tex]
